2x^2+10x-7800=0

Solution for 2x^2+10x-7800=0 equation:

2x^2+10x-7800=0

a = 2; b = 10; c = -7800;
Δ = b2-4ac
Δ = 102-4·2·(-7800)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{62500}=250$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-250}{2*2}=\frac{-260}{4}
=-65
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+250}{2*2}=\frac{240}{4}
=60
$